Question
Evaluate $\sqrt[3]{4096}$
✓
Answer
By prime factorisation method $\sqrt[3]{4096}$ $=\sqrt[3]{2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2}$ $=\sqrt[3]{(2)^3\times(2)^3\times(2)^3\times(2)^3}$
$\sqrt[3]{4096}=(2)\times(2)\times(2)\times(2)$
$\sqrt[3]{4096}=16$
$\therefore\sqrt[3]{4096}=16$
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