Question
Evaluate $\frac{\tan 65^{\circ}}{\cot 25^{\circ}}$
✓
Answer
We know : cot A = tan (90° – A)
So, cot 25° = tan (90° – 25°) = tan 65°
i.e., $\frac{\tan 65^{\circ}}{\cot 25^{\circ}}=\frac{\tan 65^{\circ}}{\tan 65^{\circ}}=1$
So, cot 25° = tan (90° – 25°) = tan 65°
i.e., $\frac{\tan 65^{\circ}}{\cot 25^{\circ}}=\frac{\tan 65^{\circ}}{\tan 65^{\circ}}=1$
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