Question
Evaluate:
$=\tan7^\circ\tan23^\circ\tan60^\circ\tan67^\circ\tan83^\circ$

Answer

We will use the properties of complementary angles.
$=\tan7^\circ\tan23^\circ\tan60^\circ\tan67^\circ\tan83^\circ$
$ =\cos83^\circ\cot67^\circ\tan60^\circ\tan67^\circ\tan83^\circ$
$=\sqrt{3}$

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