Evaluate the definite integral in Exercise: _ -1 ^ 1 (x+1) dx - Vidyadip

Question

Evaluate the definite integral in Exercise:
$\int\limits_{-1}^{1}\text{(x}+1)\ \text{dx}$

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Answer

$\text{Let}\ \text{I}=\int\limits_{-1}^{1}\text{(x+1)}\text{dx} $ $\int\text{(x}+1)\text{dx}=\frac{\text{x}^{2}}{2}+\text{x}$ By second theorem of calculus, we obtain $\text{I}=\text{F}(1)-\text{F}(-1)$$=\bigg(\frac{1}{2}+1\bigg)-\bigg(\frac{1}{2}-1\bigg)$
$=\frac{1}{2}+1-\frac{1}{2}+1$
$=2$

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