Question
Evaluate the definite integral in Exercise:
$\int\limits_{0}^{\frac{\pi}{2}}\cos2\text{x}\ \text{dx}$
$\int\limits_{0}^{\frac{\pi}{2}}\cos2\text{x}\ \text{dx}$
$\int\cos2\text{x}\ \text{dx}=\bigg(\frac{\sin2\text{x}}{2}\bigg)=\text{F}\text{(x)}$
By second fundamental theorem of calculus, we obtain
$\text{I}=\text{F}\bigg(\frac{\pi}{2}\bigg)-\text{F}(0)$
$=\frac{1}{2}\bigg[\sin2\bigg(\frac{\pi}{2}\bigg)-\sin0\bigg]$
$=\frac{1}{2}[\sin\pi-\sin0]$
$=\frac{1}{2}[0-0]=0$
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R(-11, -9)