Question
Evaluate the definite integral in Exercise:

$\int\limits_{0}^{\frac{\pi}{2}}\cos2\text{x}\ \text{dx}$

Answer

$\text{Let}\ \text{I}=\int\limits_{0}^{\frac{\text{n}}{2}}\cos2\text{x}\ \text{dx}$

$\int\cos2\text{x}\ \text{dx}=\bigg(\frac{\sin2\text{x}}{2}\bigg)=\text{F}\text{(x)}$

By second fundamental theorem of calculus, we obtain

$\text{I}=\text{F}\bigg(\frac{\pi}{2}\bigg)-\text{F}(0)$

$=\frac{1}{2}\bigg[\sin2\bigg(\frac{\pi}{2}\bigg)-\sin0\bigg]$

$=\frac{1}{2}[\sin\pi-\sin0]$

$=\frac{1}{2}[0-0]=0$

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