Question
Evaluate the definite integral in Exercise:
$\int\limits_{0}^{1}\frac{\text{dx}}{1+\text{x}^{2}}$
$\int\limits_{0}^{1}\frac{\text{dx}}{1+\text{x}^{2}}$
$\text{I}=\text{F}(1)-\text{F}(0)$
$=\tan^{-1}(1)-\tan^{-1}(0)$
$=\frac{\pi}{4}$
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| X: | 0 | 1 | 2 | 3 |
| P(X): | 0.3 | 0.2 | 0.4 | 0.1 |