Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSIntegrals5 Marks
Question
Evaluate the definite integral $\int _ { 0 } ^ { 1 } x e ^ { x ^ { 2 } } d x.$
✓
Answer
Let $I = \int _ { 0 } ^ { 1 } x e ^ { x ^ { 2 } } d x$ Put $x ^ { 2 } = t \Rightarrow 2 x d x = d t \Rightarrow d x = \frac { d t } { 2 x }$ Lower limit when x = 0, then t = 0 Upper limit when x = 1, then t = 1. $\therefore \quad I = \int _ { 0 } ^ { 1 } x e ^ { t } \frac { d t } { 2 x } = \frac { 1 } { 2 } \int _ { 0 } ^ { 1 } e ^ { t } d t$ $= \frac { 1 } { 2 } \left[ e ^ { t } \right] _ { 0 } ^ { 1 } = \frac { 1 } { 2 } \left[ e ^ { 1 } - e ^ { 0 } \right] = \frac { 1 } { 2 } [ e - 1 ]$
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