Question
Evaluate the following: $^6\text{P}_6$

Answer

We have, $^6\text{P}_6 = \frac{6!}{(6-6)!}\Big[\because^\text{n}\text{P}_\text{r}=\frac{\text{n!}}{(\text{n}-\text{r})!}\Big]$ $=\frac{6!}{0!}$ $= \frac{6\times5\times4\times3\times2\times1}{1}$ $= 720$ Hence, $^6\text{P}_6= 720$

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