Question
Evaluate the following definite integrals : $\int_4^9 \frac{1}{\sqrt{x}} d x$

Answer

$
\begin{aligned}
& \int_4^9 \frac{1}{\sqrt{x}} d x=\int_4^9 x^{-\frac{1}{2}} d x \\
= & {\left[\frac{x^{\frac{1}{2}}}{1 / 2}\right]_4^9=2[\sqrt{x}]_4^9 } \\
= & 2(\sqrt{9}-\sqrt{4}) \\
= & 2(3-2)=2
\end{aligned}
$

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