Question
Evaluate the following:
$\frac{\sin20^\circ}{\cos70^\circ}$

Answer

$\Rightarrow\frac{\sin(90^\circ-70^\circ)}{\cos70^\circ}\Rightarrow\frac{\cos70^\circ}{\cos70^\circ}$ $\big[\because\sin(90^\circ-\theta)=\cos\theta\big]$
$\Rightarrow\frac{\cos70^\circ}{\cos70^\circ}=1$

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