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Trigonometrical Ratios of Standard Angles — MATHEMATICS STD 9 — Question

ICSE BoardEnglish MediumSTD 9MATHEMATICSTrigonometrical Ratios of Standard Angles2 Marks
Question
Evaluate the following$: \frac{\tan 12^{\circ}}{\cot 78^{\circ}}$
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Answer

$ \frac{\tan 12^{\circ}}{\cot 78^{\circ}}$
$ =\frac{\tan \left(90^{\circ}-78^{\circ}\right)}{\cot 78^{\circ}}$
$ =\frac{\cot 78^{\circ}}{\cot 78^{\circ}}$
$ =1 .$

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