Question
Evaluate the following integrals:
$\int\frac{\sec^2\text{x}}{1-\tan^2\text{x}}\text{dx}$
$\int\frac{\sec^2\text{x}}{1-\tan^2\text{x}}\text{dx}$
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$\int\frac{\text{x}+5}{3\text{x}^2+13\text{x}-10}\text{ dx}$