Question
Evaluate the following integrals:
$\int\frac{1}{\text{x}^5}\text{dx}$

Answer

$\int\text{x}^{-5}\text{dx}$
$=\frac{\text{x}^{-5+1}}{-5+1}+\text{c}$
$=-\frac{1}{4}\text{x}^{-4}+\text{c}$
$=-\frac{1}{4\text{x}^4}+\text{c}$

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