Question
Evaluate the following integrals:
$\int\cos^7\text{x}\text{ dx}$

Answer

$\int\cos^7\text{x}\text{ dx}$
$=\int\cos^6\text{x}\cdot\cos\text{x}\text{ dx}$
$=\int(\cos^2\text{x})^3\cos\text{x}\text{ dx}$
$=\int(1-\sin^2\text{x})^3\cdot\cos\text{x}\text{ dx}$
Let $\sin\text{x}=\text{t}$
$\cos\text{x}\text{ dx}=\text{dt}$
Now, $\int(1-\sin^2\text{x})^3\cdot\cos\text{x}\text{ dx}$
$=\int(1-\text{t}^2)^3\text{dt}$
$=\int\big(1-\text{t}^6-3\text{t}^2+3\text{t}^4)\text{dt}$
$=\Big[\text{t}-\frac{\text{t}^7}{\text{7}}-\frac{3\text{t}^3}{3}+\frac{3\text{t}^5}{5}\Big]+\text{C}$
$=\sin\text{x}-\frac{1}{7}\sin^7\text{x}-\sin^3\text{x}+\frac{3}{5}\sin^5\text{x}+\text{C}$

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