Evaluate the following integrals: ^2_02x [x ]dx - Vidyadip

Question

Evaluate the following integrals:
$\int\limits^2_02\text{x}\big[\text{x}\big]\text{dx}$

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Answer

[x] = 0 for 0
and [x] = 1 for 1
Hence,
$=\int\limits^1_10+\int\limits^2_12\text{x}\text{ dx}$
$=\big\{\text{x}^2\big\}^2_1$
$=3$

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