Question
Evaluate the following integrals:
$\int\limits^3_2\frac{1}{\text{x}}\text{ dx}$

Answer

$\int\limits^3_2\frac{1}{\text{x}}\text{ dx}$
$=\Big[\log_\text{e}\text{x}\Big]^3_2$
$=\log_\text{e}3-\log_\text{e}2$
$=\log_\text{e}\Big(\frac{3}{2}\Big)$

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