Gujarat BoardEnglish MediumSTD 12 ScienceMathsIndefinite Integrals2 Marks
Question
Evaluate the following integrals: $\int\sqrt{3-\text{x}^2}\text{dx}$
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Answer
Let $\text{I}=\int\sqrt{3-\text{x}^2}\text{dx}$ $=\int\sqrt{(\sqrt3)^2-\text{x}^2}\text{dx}$ $\text{I}=\frac{\text{x}}{2}\sqrt{3-\text{x}^2}+\frac{3}{2}\sin^{-1}\Big(\frac{\text{x}}{\sqrt3}\Big)+\text{C}$
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