Question
Evaluate the following integrals:
$\int\tan^3\text{x}\sec^2\text{x}\text{dx}$

Answer

$\int\tan^3\text{x}\sec^2\text{x}\text{dx}$
Let $\tan\text{x}=\text{t}$
$\sec^2\text{x}\text{dx}=\text{dt}$
Now, $\int\tan^3\text{x}\sec^2\text{x}\text{dx}$
$=\frac{\text{t}^4}{4}+\text{C}$
$=\frac{\tan^4\text{x}}{4}+\text{C}$

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