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Indefinite Integrals — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsIndefinite Integrals3 Marks
Question
Evaluate the following integrals:
$\int\text{x}^2\cos2\text{x dx}$
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Answer

Let $\text{I}=\int\text{x}^2\cos2\text{x}\text{ dx}$
Using integration by parts,
$\text{I}=\text{x}^2\int\cos2\text{x dx}-\int(2\text{x}\int\cos2\text{x dx})\text{dx}$
$=\text{x}^2\frac{\sin2\text{x}}{2}-2\int\text{x}\Big(\frac{\sin2\text{x}}{2}\Big)\text{dx}$
$=\frac{1}{2}\text{x}^2\sin2\text{x}-\int\text{x}\sin2\text{x dx}$
$=\frac{1}{2}\text{x}^2\sin2\text{x}-[\text{x}\int\sin2\text{x dx}-\int(1\int\sin2\text{x dx})\text{dx}]$
$=\frac{1}{2}\text{x}^2\sin2\text{x}-\bigg[\text{x}\Big(\frac{-\cos2\text{x}}{2}\Big)-\int\Big(-\frac{\cos2\text{x}}{2}\Big)\text{dx}\bigg]$
$=\frac{1}{2}\text{x}^2\sin2\text{x}+\frac{\text{x}}{2}\cos2\text{x}-\frac{1}{2}\int(\cos2\text{x})\text{dx}$
$\text{I}=\frac{1}{2}\text{x}^2\sin2\text{x}+\frac{\text{x}}{2}\cos2\text{x}-\frac{1}{4}\sin2\text{x}+\text{C}$

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