Question
Evaluate the following:
$\int\tan^2\text{x}\sec^4\text{x dx}$
$\int\tan^2\text{x}\sec^4\text{x dx}$
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$\tan^{-1}\Bigg(\frac{1}{3}\Bigg)+\tan^{-1}\Bigg(\frac{1}{5}\Bigg)+\tan^{-1}\Bigg(\frac{1}{7}\Bigg)+\tan^{-1}\Bigg(\frac{1}{8}\Bigg)=\frac{\pi}{4}.$