Question
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow0}\frac{\sin(3+\text{x})-\sin(3-\text{x})}{\text{x}}$

Answer

$\lim\limits_{\text{x}\rightarrow0}\frac{\sin(3+\text{x})-\sin(3-\text{x})}{\text{x}}$ $=\lim\limits_{\text{x} \rightarrow0}\frac{2\cos\big(\frac{3+\text{x}+3-\text{x}}{2}\big)\sin\big(\frac{3+\text{x}-3+\text{x}}{2}\big)}{\text{x}}$ $=2\lim\limits_{\text{x} \rightarrow0}\frac{\cos3.\sin\text{x}}{\text{x}}$ $=2\cos3\lim\limits_{\text{x} \rightarrow0}\frac{\sin\text{x}}{\text{x}}$ $=2\cos3\times1$ $=2\cos3$

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