Question
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow0}\frac{\text{e}^{\tan\text{x}}-1}{\text{x}}$

Answer

$\lim\limits_{\text{x}\rightarrow0}\frac{\text{e}^{\tan\text{x}}-1}{\text{x}}$ $=\lim\limits_{\text{x}\rightarrow0}\frac{\text{e}^{\tan\text{x}}-1}{\tan\text{x}}\times\lim\limits_{\text{x}\rightarrow0}\frac{\tan\text{x}}{\text{x}}$ $=\text{log e }\times 1$ $=1$

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