Question
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow0}\frac{\text{x}^2}{\sin\text{x}^2}$

Answer

$\lim\limits_{\text{x}\rightarrow0}\frac{\text{x}^2}{\sin\text{x}^2}$ $=\frac{1}{\lim\limits_{\text{x}\rightarrow0}\frac{\sin\text{x}^2}{\text{x}^2}}{}$ $\Big[\because\ \lim\limits_{\text{x}\rightarrow0}\frac{\sin\text{x}}{\text{x}}=1\Big]$ $=\frac11$ $=1$

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