Question
Evaluate the following limit:
$\lim\limits_{\text{x}\rightarrow0}\frac{9^\text{x}-2.6^\text{x}+4^\text{x}}{\text{x}^2}$

Answer

$\lim\limits_{\text{x}\rightarrow0}\frac{9^\text{x}-2.6^\text{x}+4^\text{x}}{\text{x}^2}$
$=\lim\limits_{\text{x}\rightarrow0}\frac{\big(3^\text{x}\big)^2-2.3^\text{x}2^\text{x}+\big(2^\text{x}\big)^2}{\text{x}^2} $
$=\lim\limits_{\text{x}\rightarrow0}\Big(\frac{3^\text{x}-2^\text{x}}{\text{x}}\Big)^2$
$=\Big(\lim\limits_{\text{x}\rightarrow0}\frac{3^\text{x}-1}{\text{x}}-\lim\limits_{\text{x}\rightarrow0}\Big(\frac{2^\text{x}-1}{\text{x}}\Big)\Big)^2$
$=\Big(\text{log}\frac{3}{2}\Big)^2$

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