Question
Evaluate the following limit:
$\lim\limits_{\text{x}\rightarrow{1}}\frac{\text{x}^{15}-1}{\text{x}^{10}-1}$

Answer

$\lim\limits_{\text{x}\rightarrow{1}}\frac{\text{x}^{15}-1}{\text{x}^{10}-1}$$=\lim\limits_{\text{x}\rightarrow{1}}\frac{\frac{\text{x}^{15}-1^{15}}{\text{x}-1}}{\frac{\text{x}^{10}-1^{10}}{\text{x}-1}}$ [Dividing numerator and denominator by x - 1]
$=\frac{\lim\limits_{\text{x}\rightarrow1}\frac{\text{x}^{15}-1^{15}}{\text{x}-1}}{\lim\limits_{\text{x}\rightarrow1}\frac{\text{x}^{10}-1^{10}}{\text{x}-1}}$
Applying formula $\lim\limits_{\text{x}\rightarrow{\text{a}}}\frac{\text{x}^{\text{n}}-\text{a}^\text{n}}{\text{x}-\text{a}}=\text{na}^{\text{n}-1}$ in numerator and $\lim\limits_{\text{x}\rightarrow{\text{a}}}\frac{\text{x}^{\text{m}}-\text{a}^{\text{m}}}{\text{x}-\text{a}}=\text{ma}^{\text{m}-1}$ in denominator
$\Rightarrow\text{n}=15,\text{m}=10$
$\Rightarrow\frac{\lim\limits_{\text{x}\rightarrow1}\frac{\text{x}^{15}-1^{15}}{\text{x}-{1}}}{\lim\limits_{\text{x}\rightarrow1}\frac{\text{x}^{10}-1^{10}}{\text{x}-1}}=\frac{15(1)^{15-1}}{10(1)^{10-1}}$
$=\frac{15}{10}$
$=\frac32$

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