Question
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow{\text{a}}}\frac{\sqrt{\text{x}}+\sqrt{\text{a}}}{{\text{x}+\text{a}}}$

Answer

$\lim\limits_{\text{x}\rightarrow{\text{a}}}\frac{\sqrt{\text{x}}+\sqrt{\text{a}}}{{\text{x}+\text{a}}}=\frac{\sqrt{\text{a}}+\sqrt{\text{a}}}{\text{a}+\text{a}}$ $=\frac{2\sqrt{\text{a}}}{2\text{a}}=\frac{1}{\sqrt{\text{a}}}$

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