Question
Evaluate the following limits in Exercise: $\lim\limits_{\text{x} \rightarrow4}\frac{4\text{x}+3}{\text{x}-2}$

Answer

$​​\lim\limits_{\text{x}\rightarrow4}\frac{4\text{x}+3}{\text{x}-2}=\frac{4(4)+3}{4-2}=\frac{16+3}{2}=\frac{19}{2}$

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