Question
Evaluate the following limits: $\lim\limits_{\text{x}\rightarrow0}\frac{2\text{x}^2+3\text{x}+4}{\text{x}^2+3\text{x}+2}$

Answer

$\lim\limits_{\text{x}\rightarrow0}\frac{2\text{x}^2+3\text{x}+4}{\text{x}^2+3\text{x}+2}=\lim\limits_{\text{x}\rightarrow0}\frac{2\text{x}^2+3\text{x}+4}{(\text{x}+2)(\text{x}+1)}$ $=\frac{2(0)+3(0)+4}{(0+2)(0+1)}=\frac{4}{2}=2$

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