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Limits — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsLimits1 Mark
Question
Evaluate the following limits: $\lim _{z \rightarrow-3}\left[\frac{\sqrt{Z+6}}{Z}\right]$
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Answer

$\lim _{x \rightarrow-3}\left[\frac{\sqrt{z+6}}{z}\right] =\frac{\lim _{z \rightarrow-3} \sqrt{z+6}}{\lim _{x \rightarrow-3} z}$
$ =\frac{\sqrt{-3+6}}{-3}$
$=\frac{\sqrt{3}}{-3}$
$=\frac{-1}{\sqrt{3}}$

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