Question
Evaluate the following:
$\sec^{-1}\Big\{\sec\Big(-\frac{7\pi}{3}\Big)\Big\}$

Answer

$\sec^{-1}\Big\{\sec\Big(-\frac{7\pi}{3}\Big)\Big\}$
$=\sec^{-1}\Big\{\sec\Big(-2\pi-\frac{\pi}{3}\Big)\Big\}$
$=\sec^{-1}\Big\{\sec\Big(\frac{\pi}{3}\Big)\Big\}$
$=\frac{\pi}{3}$

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