Question
Evaluate the following:
$\frac{\sec11^\circ}{\text{cosec }79^\circ}$

Answer

$\frac{\sec11^\circ}{\text{cosec }79^\circ}\Rightarrow\frac{\sec(90^\circ-79^\circ)}{\text{cosec }79^\circ}=\frac{\text{cosec }79^\circ}{\text{cosec }79^\circ}$ $\big[\because\ \sec(90-\theta).\text{cosec }\theta\big]$
$=1$

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