Question
Evaluate the following:
$\sin^{-1}(\sin12)$
$\sin^{-1}(\sin12)$
✓
Answer
We know $\sin\big(\sin^{-1}\theta\big)=\theta$ if $-\frac{\pi}{2}\leq\theta\leq\frac{\pi}{2}$
We have
$\sin^{-1}(\sin12)=\sin^{-1}\{\sin(-\pi+12)\}$ $=12-\pi$Need a full question paper?
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