Question
Evaluate the following:
$\sin^{-1}(\sin2)$
$\sin^{-1}(\sin2)$
✓
Answer
We know $\sin\big(\sin^{-1}\theta\big)=\theta$ if $-\frac{\pi}{2}\leq\theta\leq\frac{\pi}{2}$We have
$\sin^{-1}(\sin2)=\sin^{-1}\{\sin(\pi-2)\}=\pi-2$
$\sin^{-1}(\sin2)=\sin^{-1}\{\sin(\pi-2)\}=\pi-2$
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