Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSInverse Trigonometric Functions1 Mark
Question
Evaluate the following:
$\tan^{-1}\Big(\tan\frac{6\pi}{7}\Big)$
✓
Answer
We know that $\tan^{-1}(\tan\theta)=\theta,-\frac{\pi}{2}<\theta<\frac{\pi}{2}$We have
$\tan^{-1}\Big(\tan\frac{6\pi}{7}\Big)$
$=\frac{6\pi}{7}-\pi$ $\Big(\because\ \tan^{-1}(\tan\theta)=\theta-\pi,\ \text{if }\theta\in\Big(\frac{\pi}{2},\frac{3\pi}{2}\Big)\Big)$ $=-\frac{\pi}{7}$
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