Question
Evaluate the following using identities:
$(0.98)^2$

Answer

We have,
$(0.98)^2=(1-0.02)^2$
$=(1)^2+(0.02)^2-2 \times 1 \times 0.02$
$=1+0.0004-0.04[\text { Where, } a=1 \text { and } b=0.02]$
$=1.0004-0.04$
$=0.9604$
Therefore, $(0.98)^2=0.96041$

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