Question
Evaluate the following using identities: $\big(\text{a}-0.1\big)\big(\text{a}+0.1\big)$
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Answer
We have, $\big(\text{a}-0.1\big)\big(\text{a}+0.1\big)=\text{a}^2-(0.1)^2$
$\begin{bmatrix}\because(\text{a}-\text{b})(\text{a}+\text{b})\text{a}=\text{a}:\text{b}=0.1\end{bmatrix}$
$=\text{a}^2-0.01$
$(\text{a}-0.1)(\text{a}+0.1)=\text{a}^2-0.01$
$\begin{bmatrix}\because(\text{a}-\text{b})(\text{a}+\text{b})\text{a}=\text{a}:\text{b}=0.1\end{bmatrix}$
$=\text{a}^2-0.01$
$(\text{a}-0.1)(\text{a}+0.1)=\text{a}^2-0.01$
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