Question
Evaluate:
$\int \frac{\sin 4 x}{\cos 2 x} \cdot d x$

Answer

$\int \frac{\sin 4 x}{\cos 2 x} d x$
$=\int \frac{2 \sin 2 x \cos 2 x}{\cos 2 x} d x$
$=2 \int \sin 2 x d x$
$=2\left(-\frac{\cos 2 x}{2}\right)+c$
$=-\cos 2 x+c .$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free