Question
Evaluate:
$\int \frac{x}{x+2} \cdot d x$

Answer

$\quad \int \frac{x}{x+2} d x$
$=\int \frac{(x+2)-2}{x+2} d x$
$=\int\left(\frac{x+2}{x+2}-\frac{2}{x+2}\right) d x$
$=\int 1 d x-2 \int \frac{1}{x+2} d x$
$=x-2 \log |x+2|+c .$

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