Question
Evaluate:
$\lim\limits_{\text{x} \rightarrow 0}\frac{\sin^{2}2\text{x}}{\sin^{2}4\text{x}}$

Answer

Given that $\lim\limits_{\text{x} \rightarrow 0}\frac{\sin^{2}2\text{x}}{\sin^{2}4\text{x}}$
$=\lim\limits_{\text{x} \rightarrow 0}\frac{\sin^{2}2\text{x}}{\sin^{2}2(2\text{x})}$
$=\lim\limits_{\text{x} \rightarrow 0}\frac{\sin^{2}2\text{x}}{4\sin^{2}2\text{x}.\cos^{2}2\text{x}}$
$=\frac{1}{4.\cos^{2}2\text{x}}$
Taking limits we have
$=\frac{1}{4.\cos^{2}0}=\frac{1}{4}$ 
Hence, the required is $\frac{1}{4.}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free