Question
Evalute : $\int \frac{1}{\sqrt{x}+x} d x$

Answer

$
\begin{aligned}
& \text { Let } I=\int \frac{1}{\sqrt{x}+x} d x \\
& =\int \frac{1}{\sqrt{x}(1+\sqrt{x})} d x
\end{aligned}
$
Put $1+\sqrt{ x }= t$
$
\begin{aligned}
& \therefore \frac{1}{2 \sqrt{ x }} dx = dt \\
& \therefore \frac{1}{\sqrt{ x }} dx =2 dt \\
& \therefore I =\int \frac{2 \cdot dt }{ t } \\
& =2 \int \frac{1}{ t } dt \\
& =2 \log | t |+ c \\
& \therefore I =2 \log |1+\sqrt{ x }|+ c
\end{aligned}
$

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