Question
Evalute : $\int x \log x$

Answer

$
\begin{aligned}
& \int x \log x d x=\int(\log x) \cdot x d x \\
= & (\log x) \int x d x-\int\left[\frac{d}{d x}(\log x) \int x d x\right] d x \\
= & (\log x) \cdot \frac{x^2}{2}-\int \frac{1}{x} \cdot \frac{x^2}{2} d x \\
= & \frac{1}{2} x^2 \log x-\frac{1}{2} \int x d x \\
= & \frac{x^2}{2} \log x-\frac{1}{2} \cdot \frac{x^2}{2}+c=\frac{x^2}{2} \log x-\frac{x^2}{4}+c .
\end{aligned}
$

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