Question
Evaluvate the following intregals:
$\int\frac{2\text{x}+1}{(\text{x}+1)(\text{x}-2)}\ \text{dx}$

Answer

Let $\int\frac{2\text{x}+1}{(\text{x}+1)(\text{x}-2)}=\frac{\text{A}}{(\text{x}+1)}+\frac{\text{B}}{(\text{x}-2)}$

$\Rightarrow2\text{x}+1=\text{A}(\text{x}-2)+\text{B}(\text{x}+1)$

Put $\text{x}=2$

$\Rightarrow5=3\text{B}\Rightarrow\text{B}=\frac{5}{3}$

Put $\text{x}=-1$

$\Rightarrow-1=-3\text{A}\Rightarrow\text{A}=\frac{1}{3}$

so,

$\int\frac{2\text{x}+1}{(\text{x}+1)(\text{x}-2)}\text{ dx}=\frac{1}{3}\int\frac{\text{dx}}{\text{x}+1}+\frac{5}{3}\int\frac{\text{dx}}{\text{x}-2}$

$=\frac{1}{3}\log|\text{x}+1|+\frac{5}{3}\log|\text{x}-2|+\text{C}$

Thus

$\text{I}=\frac{1}{3}\log|\text{x}+1|+\frac{5}{3}\log|\text{x}-2|+\text{C}$

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