Question
Examine the continuity of the function f(x) = 2x2 - 1 at x = 3.
Continuity at x = 3 $\mathop {\lim }\limits_{x \to 3} f\left( x \right) = \mathop {\lim }\limits_{x \to 3} \left( {2{x^2} - 1} \right) = 2{\left( 3 \right)^2} - 1 = 18 - 1 = 17$
And $f\left( 3 \right) = 2{\left( 3 \right)^2} - 1 = 18 - 1 = 17$
Since $\mathop {\lim }\limits_{x \to 3} f\left( x \right) = f\left( x \right),$ therefore, f(x) is continuous at x = 3.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.