Question
Examine the following functions for continuity.
f(x) = $\frac{1}{\text{x}-5}$
f(x) = $\frac{1}{\text{x}-5}$
For f to be defined,
x - 5
$\neq$ 0 i.e. x $\neq$ 5$\therefore$ Df= Set of real number except 5 = R = -{5}
Let c
$\neq$ 5 be any real number.Also
$^{\ \ \text{Lt}}_{\text{x}\rightarrow\text{c}}\text{f(x)}-^{\ \ \text{Lt}}_{\text{x}\rightarrow\text{c}}\Big(\frac{1}{\text x- 5}\Big)= \frac{1}{\text{c}-5}$$\therefore\ ^{\ \ \text{Lt}}_{\text{x}\rightarrow\text{c}}\text{f(x)} = \text{f(c)}$
$\therefore$ f is continuous at x = c.
But c
$\neq$ 5 is any real number$\therefore$ f is continuous at every real number $\text{c}\in \text{D}$
$\therefore$ f is continuous function.
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