Question
Expand : $(2a + b)^2$
✓
Answer
$(2a + b)^2$
$= (2a)^2 + (b)^2 + 2 \times 2a \times b ......[(a+b)^2 = a^2 + b^2+ 2ab]$
$= 4a^2 + b^2 + 4ab$
$= (2a)^2 + (b)^2 + 2 \times 2a \times b ......[(a+b)^2 = a^2 + b^2+ 2ab]$
$= 4a^2 + b^2 + 4ab$
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$
\begin{array}{l}
83,96,91,80,97,111,90,83,112,120,103,77,82,90,70 \\
68,89,85,78,105,94,97,90,89,102,113,90,106,70,84
\end{array}
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→$
\begin{array}{l}
83,96,91,80,97,111,90,83,112,120,103,77,82,90,70 \\
68,89,85,78,105,94,97,90,89,102,113,90,106,70,84
\end{array}
$
Construct a frequency table using groups
$65-75,75-85,85-95,95-105,105-115$, $115-125$.