Question
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$(2 b-b+c)^2$
$(2 b-b+c)^2$
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Answer
$(2 b-b+c)^2=[(2 a)+(-b)+(c)]^2$
$=(2 a)^2+(-b)^2+(c)^2+2(2 a)(-b)+2(-b)(c)+4(a)(c)$
$=14 a^2+b^2+c^2-4 a b-2 b c+4 a c$
$=(2 a)^2+(-b)^2+(c)^2+2(2 a)(-b)+2(-b)(c)+4(a)(c)$
$=14 a^2+b^2+c^2-4 a b-2 b c+4 a c$
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