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Factorisation of Polynomials — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsFactorisation of Polynomials2 Marks
Question
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$(-3 a+4 b-5 c)^2$
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Answer

$(-3 a+4 b-5 c)^2=[(-3 a)+(4 b)+(-5 c)]^2$
$=(-3 a)^2+(4 b)^2+(-5 c)^2+2(-3 a)(4 b)+2(4 b)(-5 c)+2(-3 a)(-5 c)$
$=9 a^2+16 b^2+25 c^2-24 a b-40 b c+30 a c$

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