Question
Expand $(4 a-2 b-3 c)^2$
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Answer
Using Identity $(x+y+z)^2=x^2+y^2+z^2+2 x y+2 y z+2 z x$,
we have $(4 a-2 b-3 c)^2=[4 a+(-2 b)+(-3 c)]^2$
$=(4 a)^2+(-2 b)^2+(-3 c)^2+2(4 a)(-2 b)+2(-2 b)(-3 c)+2(-3 c)(4 a)$
$=16 a^2+4 b^2+9 c^2-16 a b+12 b c-24 a c$
This is the required expansion.
we have $(4 a-2 b-3 c)^2=[4 a+(-2 b)+(-3 c)]^2$
$=(4 a)^2+(-2 b)^2+(-3 c)^2+2(4 a)(-2 b)+2(-2 b)(-3 c)+2(-3 c)(4 a)$
$=16 a^2+4 b^2+9 c^2-16 a b+12 b c-24 a c$
This is the required expansion.
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