Question
Expand: $\Big(3\text{m}-\frac{4}{5}\text{n}\Big)^2$

Answer

$\Big(3\text{m}-\frac{4}{5}\text{n}\Big)^2$ $=\Big(\text{3m}\Big)^2-2\times3\text{m}\times\frac{4}{5}\text{n}+\Big(\frac{4}{5}\text{n}\Big)^2​​​​​​​$ $=9\text{m}^2-\frac{24\text{mn}}{5}+\frac{16}{25}\text{n}^2$

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