Question
Expand : $\left(x+\frac{1}{2}\right)^2$
✓
Answer
$\left(x+\frac{1}{2}\right)^2$
Here $a=x$ and $b=\frac{1}{2}$
$
\begin{aligned}
& \left(x+\frac{1}{2}\right)^2=x^2+2 \times x \times \frac{1}{2}+\left(\frac{1}{2}\right)^2 \\
& \ldots .\left[(a+b)^2=a^2+2 a b+b^2\right] \\
& \therefore \quad\left(x+\frac{1}{2}\right)^2=x^2+x+\frac{1}{4} \\
&
\end{aligned}
$
Here $a=x$ and $b=\frac{1}{2}$
$
\begin{aligned}
& \left(x+\frac{1}{2}\right)^2=x^2+2 \times x \times \frac{1}{2}+\left(\frac{1}{2}\right)^2 \\
& \ldots .\left[(a+b)^2=a^2+2 a b+b^2\right] \\
& \therefore \quad\left(x+\frac{1}{2}\right)^2=x^2+x+\frac{1}{4} \\
&
\end{aligned}
$
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